C Program for Predictive Parsing

The following is the predictive parsing table for the following grammar:                                                    

S->A                                                                                                                        

A->Bb                                                                                                                       

A->Cd                                                                                                                       

B->aB 

_______________________________________________________________________________________
#include<stdio.h>
#include<conio.h>
#include<string.h>
char prol[7][10]={"S","A","A","B","B","C","C"};
char pror[7][10]={"A","Bb","Cd","aB","@","Cc","@"};
char prod[7][10]={"S->A","A->Bb","A->Cd","B->aB","B->@","C->Cc","C->@"};
char first[7][10]={"abcd","ab","cd","a@","@","c@","@"};
char follow[7][10]={"$","$","$","a$","b$","c$","d$"};
char table[5][6][10];
numr(char c)
{
    switch(c)
    {
        case 'S': return 0;
        case 'A': return 1;
        case 'B': return 2;
        case 'C': return 3;
        case 'a': return 0;
        case 'b': return 1;
        case 'c': return 2;
        case 'd': return 3;
        case '$': return 4;
       
    }
    return(2);
   
}
void main()
{
    int i,j,k;
    clrscr();
    for(i=0;i<5;i++)
    for(j=0;j<6;j++)
    strcpy(table[i][j]," ");
    printf("\nThe following is the predictive parsing table for the following grammar:\n");
    for(i=0;i<7;i++)
    printf("%s\n",prod[i]);
    printf("\nPredictive parsing table is\n");
    fflush(stdin); for(i=0;i<7;i++)
    {
        k=strlen(first[i]);
        for(j=0;j<10;j++)
        if(first[i][j]!='@')
        strcpy(table[numr(prol[i][0])+1][numr(first[i][j])+1],prod[i]);
       
    }
    for(i=0;i<7;i++)
    {
        if(strlen(pror[i])==1)
        {
            if(pror[i][0]=='@')
            {
                k=strlen(follow[i]);
                for(j=0;j<k;j++)
                strcpy(table[numr(prol[i][0])+1][numr(follow[i][j])+1],prod[i]);
            }
           
        }
       
    }
    strcpy(table[0][0]," ");
    strcpy(table[0][1],"a");
    strcpy(table[0][2],"b");
    strcpy(table[0][3],"c");
    strcpy(table[0][4],"d");
    strcpy(table[0][5],"$");
    strcpy(table[1][0],"S");
    strcpy(table[2][0],"A");
    strcpy(table[3][0],"B");
    strcpy(table[4][0],"C");
    printf("\n--------------------------------------------------------\n");
    for(i=0;i<5;i++)
    for(j=0;j<6;j++)
    {
        printf("%-10s",table[i][j]);
        if(j==5)
        printf("\n--------------------------------------------------------\n");
       
    }
    getch();
   
}